Answer:
Inductance per unit length, [tex]\frac{L}{l} = 7.02 * 10^{-7} H/m[/tex]
Explanation:
Radius of the wire, a = 2.80 mm
Currents carried by each of the wires, i = 5.00 A
Center-to-Center Separation, W = 19.0 cm
The flux in the wires is given by the equation, ∅ = Li
The Net flux of the region between the wires is given by the equation:
[tex]\phi = \frac{l \mu_0 i}{\pi} ln(\frac{W-a}{a})[/tex]
Divide both sides by l to get the net flux per unit length
[tex]\phi/l = \frac{ \mu_0 i}{\pi} ln(\frac{W-a}{a})\\\phi/l = \frac{ 4 \pi * 10^{-7} i}{\pi} ln(\frac{0.019-0.0028}{0.0028})\\\phi/l = 7.02 * 10^{-7} i\\\frac{Li}{l} = 7.02 * 10^{-7} i\\\frac{L}{l} = 7.02 * 10^{-7} H/m[/tex]
