Answer:
(a)Exponential
(b)[tex]P(t)=4.70(1.0136)^t[/tex]
(c)The price of milk next year will be: $4.76
(d)5 years
Step-by-step explanation:
The price of a gallon of milk has been rising about 1.36% per year since 2000.
(a)Since the price grows by a percentage (or constant factor) each year, an exponential function would be best to model the scenario.
(b)The exponential growth model is given as:
[tex]P(t)=P_0(1+r)^t$ where:\\P_0$=Initial Price\\r=Growth factor\\t=time (in years, for this case)[/tex]
The independent variable in the function is t. This represents the number of years since 2000.
(c)
[tex]I$nitial Price, P_0=\$4.70\\r=1.36\%=0.0136\\P(t)=4.70(1+0.0136)^t\\\\P(t)=4.70(1.0136)^t[/tex]
Therefore, the price of milk next year will be:
[tex]P(1)=4.70(1.0136)^1=\$4.76[/tex]
(d)We want to determine how long it will take for the price to top $5.
P(t)=$5
[tex]5=4.70(1.0136)^t\\$Divide both sides by 4.7$\\(1.0136)^t=\frac{5}{4.7} \\$Change to logarithm form\\t=Log_{1.0136}\frac{5}{4.7}\\t=4.58[/tex]
Therefore, in exactly 4.58 years, the milk price would be $5. Therefore, by the 5th year, the milk price would top $5.