Answer:
2205m³ to the nearest tenth
Step-by-step explanation:
Volume of a cone is
[tex] \frac{1}{3} \pi {r}^{2} h[/tex]
where r is the radius
h is the height
radius = diameter / 2
from the question
radius = 18/2 = 9m
height = 26m
Volume of the cone is
[tex] \frac{1}{3} \pi \times {9}^{2} \times 26 \\ = \frac{1}{3} \pi \times 2106 \\ = 702\pi \\ \\ = 2205.4[/tex]
The final answer is
2205m³ to the nearest tenth
Hope this helps you
