Question

The leaning tower of Pisa is about 56 meters tall. A ball released from the top takes 3.4 seconds to reach the ground. The final velocity of the ball before it hits the ground is 33 meters/second. Assuming that the ball experienced a constant acceleration throughout this descent, calculate the magnitude of the acceleration. A. 0.24 g

Answer 1

Answer:

Magnitude of the acceleration(g) = 9.7 meters/second²

Explanation:

Given:

Height of tower = 56 meter

Time taken = 3.4 second

Final velocity (v) = 33 meters/second

Initial velocity (u) = 0 meters/second

Find:

Magnitude of the acceleration(g)

Computation:

Using first equation of motion:

v = u + at

Magnitude of the acceleration(g)

v = u + gt

33 = 0 + g(3.4)

g = 33 / 3.4

g = 9.7 meters/second²

Magnitude of the acceleration(g) = 9.7 meters/second²