Answer:
200 V/m
Explanation:
The computation of the magnitude of the electric field is shown below:
Data provided in the question
DC power supply = 24 volts
The Point on X-axis = 12 cm
The Point on X-axis = 8 cm
Based on the above information, the magnitude of the electric field is
[tex]|\vec{E}|=\frac{\Delta V}{\Delta x}\\\\=\frac{24 V}{12\times10^{-2}m}\\\\=\mathbf{200\ V/m}[/tex]
As the plates are very big so we considered that the electric field inner could be bring out as a uniform and so it would be the same for 8 cm as well