Identical 4.0-uC (microCoulomb) charges are placed on the y axis at y = +/-4.0 m. (plus or minus 4.0 m) Point A is on the x axis at x = +3.0 m. Determine the electric potential of point A (relative to zero at the origin).

Respuesta :

Answer:

Explanation:

Distance of charges placed on y axis from given point on x axis

= √ (3² + 4² )

= 5 m

Potential at point A due to given charge

= Q / 4πε₀ R

Potential due to each of charges

= 4 x 10⁻⁶ x 9 x 10⁹ / 5  [ 1/ 4πε₀ = 9 x 10⁹ ]

= 7.2 x 10³ V

Potential due to both the charges

= 2 x 7.2 x 10³

= 14.4 kV .

ACCESS MORE