Answer:
Explanation:
Distance of charges placed on y axis from given point on x axis
= √ (3² + 4² )
= 5 m
Potential at point A due to given charge
= Q / 4πε₀ R
Potential due to each of charges
= 4 x 10⁻⁶ x 9 x 10⁹ / 5 [ 1/ 4πε₀ = 9 x 10⁹ ]
= 7.2 x 10³ V
Potential due to both the charges
= 2 x 7.2 x 10³
= 14.4 kV .