Complete question:
The pv diagram in the figure below (see attached file) shows a process abc involving 0.920 of an ideal gas.
How much heat had to be put in during the process to increase the internal energy of the gas by 2.00×10⁴ J ?
Answer:
The amount of heat required to increase the internal energy of the gas is 2,000 J
Explanation:
Work done in gas is given as;
W = ΔPV
The pressure of the gas at "a" = 2 x 10⁵ Pa
The pressure of the gas at "b" = 5 x 10⁵ Pa
The volume of the gas at "a" = 0.01 m³
The volume of the gas at "b" = 0.07 m³
The work done = (5 x 10⁵ Pa - 2 x 10⁵ Pa) x (0.07 m³ - 0.01 m³)
The work done = 3 x 10⁵ Pa x 0.06 m³
The work done = 18000 J
The work done = 1.8 x 10⁴ J
Determine, the amount of heat required to increase the internal energy of the gas by 2.00×10⁴ J.
1.8 x 10⁴ J + H = 2.00 x 10⁴ J
H = 2.00 x 10⁴ J - 1.8 x 10⁴ J
H = 0.2 x 10⁴ J
H = 2,000 J
Therefore, the amount of heat required to increase the internal energy of the gas by 2.00×10⁴J is 2,000 J
