Answer:
13
Step-by-step explanation:
Given: A rectangle ABCD in which diagonals AC and BD intersect at E.
AE = X + 11
CE = 6x + 1
To find: Find AC
solution,
The diagonals at a rectangle bisects each other. Hence, AE = EC
x + 11 = 6x + 1
Move the variable to L.H.S and change its sign
X - 6x + 11 = 1
Move the constant to R.H.S and change its sign
x - 6x = 1 - 11
Simplify
-5x = -10
Divide both side of the equation by 5
-5x/5 = -10/5
Calculate
-x = -2
The minus sign (-) will be cancelled on both sides
X = 2
Again,
EC = 6x + 1
= 6 * 2 + 1
= 12 + 1
= 13
Hope this helps...
Good luck on your assignment...
