Question

PLEASE HELP! The composite figure is made up of a cone and a half sphere. The radius of the half sphere is 6 cm. What is the volume of the composite figure? Use 3.14 for Pi. Round to the nearest hundredth.

Answer 1

Answer:

904.32 cm^3

Step-by-step explanation:

V = (1/3)(pi)r^2h + (1/2)(4/3)(pi)r^3

V = (1/3)(3.14)(6 cm)^2(12 cm) + (1/2)(4/3)(3.14)(6 cm)^3

V = 904.32 cm^3

Answer 2

The volume of the figure would be the combination of the volume of the cone and the hemisphere that is 904.32 cm^3.

How to find volume of a right circular cone?

Suppose that the radius of the considered right circular cone be 'r' units.

And let its height be 'h' units.

Then, its volume is given as:

$V = \dfrac{1}{3} \pi r^3 h \: \rm unit^3$

Right circular cone is the cone in which the line joining the peak of the cone to the center of the base of the circle is perpendicular to the surface of its base.

The composite figure is made up of a cone and a half-sphere.

The radius of the half-sphere is 6 cm.

The volume of the figure would be the combination of the volume of the cone and the hemisphere.

The volume of the figure is

$V = (1/3)(\pi)r^2h + (1/2)(4/3)(\pi)r^3\\V = (1/3)(3.14)(6 cm)^2(12 cm) + (1/2)(4/3)(3.14)(6 cm)^3\\V = 904.32 cm^3$

Learn more about the volume of cone here:

https://brainly.com/question/26093363

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