Question

$( \frac{1}{7} x - \frac{1}{8}y) \times (7 {x}^{2} - 8 {y}^{2})$
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Answer 1

Answer:

$x^{3}-\frac{8}{7} xy^{2} -\frac{7}{8}x^{2}y+y^{3}$

Step-by-step explanation:

$(\frac{1}{7} x -\frac{1}{8} y)*(7x^{2} - 8y^{2}) =\frac{1}{7} x*7x^{2} -\frac{1}{7} x*8y^{2}-\frac{1}{8} y*7x^{2} + \frac{1}{8} y*8y^{2}=\\\\=x^{3}-\frac{8}{7} xy^{2} -\frac{7}{8}x^{2}y+y^{3}$