Can someone answer this question?
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Answer:
No solution.
Step-by-step explanation:
(1/12)^-2b * 12^(-2b + 2) = 12
1/12 is basically the same thing as 12^-1.
12^(-1 * -2b) * 12^(-2b + 2) = 12
12^2b * 12^(-2b + 2) = 12
12^(2b - 2b + 2) = 12
12^2 = 12
Since the answers don't match up, the answer will be no solution.
Hope this helps!
Answer:
no solution
Step-by-step explanation:
(1/12) ^ (-2b) + 12 ^(-2b+2) = 12
Rewriting 1/12 as 12 ^ -1
(12^ -1) ^ (-2b) + 12 ^(-2b+2) = 12
We know a^b^c = a^ ( b*c)
(12) ^ (-1*-2b) + 12 ^(-2b+2) = 12
(12) ^ (2b) + 12 ^(-2b+2) = 12
We know that a^ ( b+c) = a^ b * a^c
12 ^ 2b + 12 ^ -2b * 12 ^ 2 = 12
12 ^ 2b + 144 * 12 ^ -2b = 12
Let 12 ^ b = u
u^2 + 144/u^2 = 12
Multiply by u^2
u^4 +144 = 12u^2
Subtract 12 u^2
u^4 -12u^2 +144 =0
There is no real solution