Question

Can I get help with this problem?

Answer 1

Answer:

26.19 mi

Solution,

Arc length:

$2\pi \: r \times \frac{theta \: }{360 } \\ = 2 \times \frac{22}{7} \times 10 \times \frac{150}{360} \\ = 26.19 \: mi$

hope this helps...

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