Answer:
[tex]the \: recursive \: formula \: is \\ tn = 6( {4}^{n - 1} )[/tex]
Answer is given below with explanations.
Step-by-step explanation:
[tex]the \: given \: geometric \: sequence \: is \\ 6, \: - 24, \: 96, \: - 384 \\ the \: first \: term \: is \: 6 \: and \: the \: common \: ratio \: is \: - 4 \\ the \: {n}^{th} term \: of \: the \: geometric \: sequence \: is \\ tn = a {r}^{n - 1} \\ here \: first \: term \:( a) = 6 \\ common \: ratio \: (r) = - 4 \\ on \: substituting \: the \: values \: in \: formula \\ tn = 6( { - 4}^{n - 1} ) \\ the \: above \: mentioned \: formula \: is \: \\ the \: recursive \: formula \: \\ for \: geometric \: sequence.[/tex]
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