Question

A physicist wants to study the motion of a car.

a. The physicist measures how long it takes a car to go 50 miles. How many
kilometers is this? (Note: 1 mi = 1.61 km)

b. In another experiment, the car travels 22.3 miles. How many yards is this?
(Note: 1 mi = 5280 ft; 1 yd = 3 ft)

Answer 1

Answer:

a.

Explanation:

in a

$1 mi = 1.61km$

so,in 50 miles

$50 mi = 50 \times 1.61$

$= 80.5 \: km$

in b

$1 \: mi = 1760 \: yd$

so in 22.3 miles

$22.3 = 22.3 \times 1760$

$= 39248 \: yd$