Answer:
Answer is 117.86 mm^2
Answer is given below with explanations.
Step-by-step explanation:
[tex]in \: the \: figur \: there \: are \: two \: parllelograms \\ intersecting \: a \: triangle \\ area \: of \: 1 \: parallelogram \: = \: bh \: \\ here \: base\: (b) = 20 \:mm \: \: an d \: height \: (h) = 4 \: mm \\ area \: of \: 1 \: parallelogram \: = 20 \times 4 \\ \: \: = 80 \: {mm}^{2} \\ area \: of \: 2 \: parallelogram \: = bh \\ here \: base \: (b) = 32 \: mm \\ height \: (h) = 2 \: mm \\ area \: of \: 2 \: parallelogram \: = 32 \times 2 \\ \: \: = 64 {mm}^{2} \\ in \: the \: v \: shaped \: figure \: there \: s \: a \: triangle \\ area \: of \: triangle \: is \: calculated \: using \: \\ heron \: s \: formula \\ area \: of \: triangle \: = 26.14 \\ area \: of \: v \: block \\ = area \: of \: 1 \: parallelogram \: + area \: of \: 2 \: parallelogram \: - area \: of \: triangle \\ = 80 + 64 - 26.14 \\ \: \: = 117.86 \: {mm}^{2} [/tex]
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