Answer:
4.94g of material
Explanation:
Partition coefficient (Kp) of a substance is defined as the ratio between concentration of organic solution and aqueous solution, that is:
Kp = 8 = Concentration in Ethyl acetate / Concentration in water
100mL of a 5% solution contains 5g of material in 100mL of water. Thus:
8 = X / 100mL / (5g-X) / 100mL
Where X is the amount of material in grams that comes to the organic phase.
8 = X / 100mL / (5g-X) / 100mL
8 = 100X / (500-100X)
4000 - 800X = 100X
4000 = 900X
4.44g = X
Thus, in the first extraction you will lost 4.44g of material from the aqueous phase.
And will remain 5g-4.44g = 0.56g.
In the second extraction:
8 = X / 100mL / (0.56g-X) / 100mL
8 = 100X / (56-100X)
448 - 800X = 100X
448 = 900X
0.50g = X
In the second extraction, you will extract 0.50g of material
Thus, after the two extraction you will lost:
4.44g + 0.50g = 4.94g of material
