A dihybrid cross SS tt × ss TT is used to make an F1 generation. In the cross S is dominant, but T and t exhibit incomplete dominance. Assuming independent assortment, how many phenotypic classes are expected in F2 when crossing F1 individuals to each other?

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03-07-2020
Biology

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A dihybrid cross SS tt × ss TT is used to make an F1 generation. In the cross S is dominant, but T and t exhibit incomplete dominance. Assuming independent assortment, how many phenotypic classes are expected in F2 when crossing F1 individuals to each other?

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ajeigbeibraheem ajeigbeibraheem · Answer 1 · 2020-07-08T02:52:50+02:00

Answer:

Explanation:

Given that:

A dihybrid cross SS tt × ss TT is used to make an F1 generation

where;

S = dominant

T and t exhibit incomplete dominance.

According to Mendelian's Law of Independent Assortment.

The cross between SS tt × ss TT will be as follows:

If self crossing occurs first, the following traits will be used for the F1 cross

S S

t St St

s s

T sT sT

St St St St

sT SstT SstT SstT SstT

Thus; the F1 generation produce offsprings that are all heterozygous SstT

For the F2 generation now;

We have

SsTt × SsTt

S s

T ST sT

t St st

ST St sT st

ST SSTT SSTt SsTT SstT

St SSTt SStt sSTt sStt

sT SsTT SstT sSTT sstT

st SsTt Sstt ssTt sstt

From the above F2 generation; we have the following offspring.

SSTT ---- 3 = 3/16 = 0.1875 = 18.75 %

SStT ----- 6 = 6/16 = 0.375 = 37.5%

Sstt ------ 3 = 3/16 = 0.1875 = 18.75 %

ssTT ------ 1 = 1/16 = 0.0625 = 6.25%

ssTt ----- 2 = 2/16 = 0.125 = 12.5%

sstt ----- 1 = 1/16 = 0.0625 = 6.25%

abhishekprakash2625 abhishekprakash2625 · Answer 2 · 2022-02-01T18:53:14+01:00

The branch of science that deals with genes and inheritance are called genetics. There are two types of an allele in the gene pair, one allele is called recessive and the other is dominant.

The correct answer to the question is mentioned below.

Dihybrid cross

A cross in which where two-character are crossed.
According to the question, the two-character T and S are crossed together to produced the offspring.

In the cross, the dominant character has a ratio is 3/4 and the recessive character has 1/4.

The ratio of the given character is as follows:-

From the above F2 generation; we have the following offspring.

SSTT ---- 3 = 3/16 = 0.1875 = 18.75 %
SStT ----- 6 = 6/16 = 0.375 = 37.5%
Sstt ------ 3 = 3/16 = 0.1875 = 18.75 %
ssTT ------ 1 = 1/16 = 0.0625 = 6.25%
ssTt ----- 2 = 2/16 = 0.125 = 12.5%
sstt ----- 1 = 1/16 = 0.0625 = 6.25%

Hence, the correct answer is mentioned above.

For more information about the genes, refer to the link:-

https://brainly.com/question/264225