Answer:
Sin P=15/17
Sec p=17/8
solution,
[tex]a. \: 17 \: cos \: p = 8 \\ cos \: p = \frac{8}{17} \\ sec \: p = \frac{1}{cos \: p} \\ \: \: \: \: \: \: \: = \frac{17}{8} \\ \\ b. \: sin \: p = \sqrt{1 - ( \frac{8}{17}) ^{2} } \\ \: \: \: \: \: \: \: \: \: \: = \sqrt{1 - \frac{64}{289} } \\ \: \: \: \: \: \: \: \: = \sqrt{ \frac{1 \times 289 - 64}{289} } \\ \: \: \: \: \: \: \: \: \: = \sqrt{ \frac{225}{289} } \\ \: \: \: \: \: \: \: \: = \sqrt{ { \frac{15}{ {17}^{2} } }^{2} } \\ \: \: \: \: \: \: \: = \frac{15}{17} [/tex]
hope this helps...
Good luck on your assignment..
