Question

A rectangle is eight inch long and its diagonal is ten inches. What's the width of the rectangle?

Answer 1

Diagonal = $\sqrt{length^{2} + width^{2} }$

10 = $\sqrt{8^{2} + width^{2} }$

10 = $\sqrt{64 + width^{2} }$

100 = 64 + $width^{2}$

$width^{2}$ = 100 - 64

$width^{2}$ = 36

width = $\sqrt{36}$

width = 6 inches

Answer 2

Answer:

the answer is 6 inches

Step-by-step explanation:

To find the diagonal we use the Pythagorean Theorem:

l² + w² = d² where the is d hypotenuse

8² + w² = 10²

64 + w² = 100

w² = 100 - 64

w² = 36

w = √36

w = 6

therefore the width of the rectangle is 6 inches

I hope this was helpful !!!!!!!!!