Question

Could someone please help me with this: Solution set of lx^2+mx+n=0 is?

Answer 1

Answer:

Quadratic equations have the solution

x = [-b +-sqr root(b^2 -4ac)] / 2a

In the given equation a = l; b = m and c = n So,

x = [-m +-sqr root(m^2 -4*l*n)] / 2*l

Step-by-step explanation: