Question

PLEASE HELP!!

The diagram shows the cross-section ABCD of a sculpture in the shape of
a prism
with perpendicular height 9 cm.
AB = 14 cm, CD = 8cm, AD = 12cm and BC = 10cm
The height of the prism is also 9 cm.
What is the total surface area of the sculpture in cm2?
Type each step of your working on a separate line.

Answer 1

Answer:

99   (cm^2)

Step-by-step explanation:

Perpendicular to the AB segment at points D and C, the graph is divided into two triangles and a rectangle.

The area of the middle rectangle is equal to 8*9=72. The hypotenuse of the right triangle is 10cm, and one of the right sides is 9cm, so the other side is SQRT (10^2-9^2) = SQRT (19).

One side of the left triangle is 9cm long and the other side is 14-8-sqRT (19) = 6-sqRT (19) cm.

Then, add the area of the three parts.

72+9*sqrt（19）/2+9*（6-sqrt（19））/2=99    (cm^2)