Question

Calculate the electric potential due to a dipole whose dipole moment is 5.2×10−30 C⋅m at a point r = 2.8×10−9 m away. Suppose that r≫ℓ, where ℓ is the distance between the charges in the dipole.

Answer 1

Answer:

V = 8.01*10^-12 V

Explanation:

In order to calculate the electric potential produced by the dipole you use the following formula:

$V=k\frac{p}{r^2}$        (1)

k: Coulomb's constant = 8.98*10^9Nm^2/C^2

p: dipole moment = 5.2×10−30 C⋅m

r: distance to the dipole = 2.8*10^-9m

You replace the values of the parameters:

$V=(8.98*10^9Nm^2/C^2)\frac{5.2*10^{-30}Cm}{(2.8*10^{-9}m)}\\\\V=8.01*10^{-12}V$

The electric potential of the dipole is 8.01*10^-12V