State whether the decay is linear or​ exponential, and answer the associated question. The value of a car is decreasing by 9​% per year. If the car is worth ​$11 comma 000 ​today, what will it be worth in two​ years? g

Respuesta :

Answer:

  • Exponential
  • A(2)=$9109.10

Step-by-step explanation:

Since the value of the car decreases by a common factor each year, the decay is exponential.

An exponential decay function is of the form

[tex]A(t)=A_0(1-r)^t$ where:\\Initial Value, A_0=\$11,000\\$Decay Factor, r=9%=0.09[/tex]

Therefore, the function modeling the car's decay is:

[tex]A(t)=11000(1-0.09)^t[/tex]

We want to determine the car's value in two years.

When t=2

[tex]A(2)=11000(1-0.09)^2\\A(2)=\$9109.10[/tex]

The value of the car in 2 years will be A(t)=$9109.10

Final value of the car after 2 years will be $9109.10

 Value of the car decay by 9%.

Since, 9% is a common factor by which the value of car is decreasing,

Therefore, decay will be exponential.

Expression for the exponential decay is given by,

[tex]P=P_0(1-\frac{r}{100} )^t[/tex]

Here, [tex]P=[/tex] Final price

[tex]P_0=[/tex] Initial price

[tex]r=[/tex] Rate of decay

[tex]t=[/tex] time

  If initial price of the car [tex]P_0=11000[/tex], rate of decay [tex]r=0.09[/tex] and [tex]t=[/tex] Number of years

By substituting the values in the expression,

P = [tex]11000(1-0.09)^2[/tex]

  = 11000(0.91)²

  = $9109.10

   Therefore, final value of the car after 2 years will be $9109.10

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