Answer:
Tl³⁺ + Sn²⁺ → Tl⁺ + Sn⁴⁺
Explanation:
In a redox reaction, one compound is oxidized (Loosing electrons) whereas the other compound is reduced (Gaining electrons). In the reaction, the half-reactions of oxidation and reduction are:
Sn²⁺ → 2e⁻ + Sn⁴⁺ (Oxidation: Loosing electrons)
Tl³⁺ + 2e⁻ → Tl⁺ (Reduction: Gaining electrons)
The sum of both reactions gives:
Tl³⁺ + Sn²⁺ + 2e⁻ → Tl⁺ + 2e⁻ + Sn⁴⁺
Subtracting the electrons: