Answer:
Dimensions: 18.667 x 18.667 x 14 inches
Volume: 4878.22 in3
Step-by-step explanation:
If the length plus the girth does not exceed 84 inches, we have:
[tex]length + (2*width+2*height) = 84[/tex]
The box has a square base, to length = width, then we have:
[tex]length + (2*length+2*height) = 84[/tex]
[tex]3*length+2*height = 84[/tex]
The volume of the box is given by the equation:
[tex]Volume = length * width * height = length^2*height[/tex]
From the first equation, we have:
[tex]height = (84 - 3*length)/2[/tex]
Using this height in the volume equation, we have:
[tex]Volume = length^2*(84-3*length)/2[/tex]
[tex]Volume = 42length^2-1.5*length^3[/tex]
To find the maximum volume, we can find the value of length that makes the derivative of the volume in relation to the length equal zero:
[tex]dV/dl = 84length - 4.5*length^2 = 0[/tex]
[tex]84length = 4.5*length^2[/tex]
[tex]length = 84/4.5 = 18.667\ inches[/tex]
So the width, the height and the volume of the package are:
[tex]width = length = 18.667\ inches[/tex]
[tex]height = (84 - 3*18.667)/2 = 14\ inches[/tex]
[tex]Volume = 42*(18.667)^2-1.5*(18.667)^3 = 4878.22\ in3[/tex]