Question

The vertex form of a quadratic function is f(x) = a(x - 1)2 + k. What is the vertex of each function? Match the function
rule with the coordinates of its vertex.
f(x) = 9(x + 5)2 - 6
(6,9)
f(x) = 6(x + 9)2 - 5
(5,6)
f(x) = 9(x - 5)2 + 6
(-9.-5)
f(x) = 6(x - 5)2 - 9
U (-5,-6)
(5.-9)
f(x) = 5(x - 6) +9
Done
Intro

Answer 1

Answer:

f(x) = 9(x + 5)2 - 6 (-5,-6)

f(x) = 6(x + 9)2 - 5 (-9,-5)

f(x) = 9(x - 5)2 + 6 (5,6)

f(x) = 6(x - 5)2 - 9. (5,-9)

f(x) = 5(x - 6) +9. (6,9)

Step-by-step explanation:

To find the vertex: for the x-coordinate, take the "h" in the parentheses (x + h) and reverse its sign. For the y-coordinate, use the "k" term as-is.

Answer 2

The coordinates of the vertex of the equations are:

1. f(x) = 9(x + 5)^2 - 6; Vertex = (-5,-6)
2. f(x) = 6(x + 9)^2 - 5; Vertex = (-9,-5)
3. f(x) = 9(x - 5)2 + 6; Vertex =(5,6)
4. f(x) = 6(x - 5)^2 - 9; Vertex = (5,-9)
5. f(x) = 5(x - 6) +9; Vertex = (6,9)

How to determine the vertex of the quadratic functions?

The vertex form of the quadratic function is given as:

y = a(x -h)^2 + k

Where:

Vertex = (h,k)

Using the above highlight, the coordinates of the vertex of the equations would be:

f(x) = 9(x + 5)^2 - 6

Vertex = (-5,-6)

f(x) = 6(x + 9)^2 - 5

Vertex = (-9,-5)

f(x) = 9(x - 5)2 + 6

Vertex =(5,6)

f(x) = 6(x - 5)^2 - 9

Vertex = (5,-9)

f(x) = 5(x - 6) +9

Vertex = (6,9)

Read more about vertex quadratic functions at:

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