Answer & Step-by-step explanation:
In this problem, we are given two functions.
s(x) = 2x + 1
r(x) = -x² + 3x
We are asked to find the difference between s(x) and r(x).
(2x + 1) - (-x² + 3x)
Distribute the negative to the second parentheses.
2x + 1 + x² - 3x
Combine like terms and put the equation in standard form. This means the exponents should be in descending order.
x² - x + 1
So, (s - r)(x) equals x² - x + 1
Answer:
(2x-1) - (-x^2 +3x)
THEN
x^2 - x + 1
Step-by-step explanation:
Since youre subtracting r from s...
s(x) = 2x + 1
r(x) = -x^2 + 3x
you subtract the two to get an equation for the first step.
(s-r)(x) = (2x+1) - (-x^2 +3x)
for the next step, you're simplifying...
distribute the minus: (2x+1) + x^2 - 3x
combine like terms: x^2 + 1 - 1x
which gives you the answer of...
x^2 - x + 1
Hope this helps!!
