Answer:
Candidate A should be selected due to lower costs
Explanation:
Cost with Candidate A = Sum (Cost of unit × Number of units)
Cost with Candidate A = 6(400) + 4(100) + 10(500) + 3(500)
Cost with Candidate A = $9300
(TABLE ATTACHED BELOW)
Cost with Candidate B = Sum (Cost of unit × Number of units)
Cost with Candidate B = 6(400) + 4(100) + 14(500) + 3(500)
Cost with Candidate B = $11300
In the solution we are supplying 500 units from Source 2 and Candidate B to Plant 3 and Plant 2 respectively. The cost per unit = 14+3 = $17. If we interchange the source to the plant the cost is 7+8 = $15
Optimal Cost with Candidate B = 6(400) + 4(100) + 8(500) + 7(500)
Optimal Cost with Candidate B = $10300
(TABLE ATTACHED BELOW)