Answer:
mean of the sample μ₁ = $0.27
Standard deviation of the sample σ₁ = $0.83
Step-by-step explanation:
Step(i):-
given mean of the population 'μ' = $19.67
Mean of the sample
[tex]= \frac{mean}{n} = \frac{19.67}{72} = 0.27[/tex]
Mean of the sample μ₁ = 0.27
Step(ii):-
Given standard deviation of the population (σ) = $7.02
Standard deviation of sample
[tex]= \frac{mean}{\sqrt{n} } = \frac{7.02}{\sqrt{72} } = 0.827[/tex]
Standard deviation of sample = 0.827≅ 0.83
Final answer:-
mean of the sample μ₁ = $0.27
Standard deviation of the sample σ₁ = $0.83