Respuesta :
Answer:
a
The number of linearly independent vectors needed to span M2,4. N =8
b
The dimension of [tex]M_{2,4}[/tex] is 8
Step-by-step explanation:
From the question we are told that
The vector space is an [tex]M_{2,4}[/tex] matrix
Now the number of linear linearly independent vectors needed to span M2,4.
is evaluated as
[tex]N = 2 * 4 = 8[/tex]
this is due to the fact that each entry of the matrix is independent
Given that there are eight independent in the vector space the dimension of
[tex]M_{2,4}[/tex] is 8
a The number of linearly independent vectors needed to span M2,4. N =8
b The dimension of M2, 4 is 8.
Calculation of the number of linearly independent vectors and dimensions:
Since there is vector space i.e. M2, 4
So, here n be = 2(4) = 8
Also, each entry of the matrix should be considered independent. Therefore, the dimension should also be 8.
Hence,
a The number of linearly independent vectors needed to span M2,4. N =8
b The dimension of M2, 4 is 8.
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