Answer:
Following are the answer to this question:
Explanation:
The most stable carbocation is: [tex]C_9H^{+}_{11}[/tex]
Degree of the unsaturation
[tex]= \frac{2C+2+N-X-H}{2}[/tex]
Where,
C=9, N=0, X=0, H=12
[tex]\ Degree \ of \ the \ unsaturation= \frac{2\times 9+2+0-0-12}{2}[/tex]
[tex]= \frac{20-12}{2}\\= \frac{8}{2}\\=4[/tex]
which means 3 double bonds and 1 ring.