Answer: 190μm
Explanation:
Given the following :
Mass of physicist (m1)= 72kg
Mass of equipment(m2) = 400kg
Height of antenna (L) = 610m
Radius(r) = 0.150
Youngs modulus of steel = 2 × 10^11 Nm^-2
Recall the young's modulus(y) formula :
Y = stress / strain
Stress = force (F) / area(A)
Strain = extension(E) / length (L)
Y = (F/A) ÷ (E/L)
Y = F/A × L/E
Y = FL /AE
Y × AE = FL
E = FL / YA
Area(A) = πr^2
A = π × 0.150^2 = 0.070695m^2
Force (F) = mg
(400 + 72) × 9.8m/s^2 = 4625.6N
THEREFORE :
E = (4625.6 × 610) / (2 × 10^11 × 0.070695)
E = 2821616 / 0.14139 × 10^11
E = 2821616 / 14139000000
E = 0.00019956262819152
E = 0.0001995
E = 1.995 × 10^-4m = 199.5 × 10^-6
Approx E = 190μm