Answer:
A . 4.08
The average number of people you should expect to find wearing their seat belt is
μ= n p = 4.08
Step-by-step explanation:
Step(i):-
Given the probability that drivers wear seat belts
p = 68% =0.68
Given sample size 'n' =6
we will use binomial distribution
mean of the binomial distribution μ= n p
step(ii):-
The average (0 r) mean of the binomial distribution
μ= n p = 6 X 0.68 = 4.08
The standard deviation of the binomial distribution
σ = √npq
= [tex]\sqrt{6 X 0.68 X 0.32} = 1.142[/tex]
Final answer:-
The average number of people you should expect to find wearing their seat belt is
μ = 4.08
The standard deviation of the people you should expect to find wearing their seat belt is
σ = 1.142
