Answer:
0.057 L
Explanation:
Data obtained from the question include:
Initial temperature (T1) = 25°C
Initial pressure (P1) = 1 atm
Initial volume (V1) = 10 L
Final temperature (T2) = 25°C
Final pressure = 175 atm
Final volume =.?
From the data obtained from the question, we can see that the temperature is constant. Therefore, we shall apply the Boyle's law equation to determine the new volume of air. This is illustrated below:
P1V1 = P2V2
1 x 10 = 175 x V2
Divide both side by 175
V2 = 10/175
V2 = 0.057 L
Therefore, the volume of air which can be stored when the tank is compressed is 0.057 L
