Question

Hence, the force of gravitation between Earth and Jupiter is 8.16 * 10 N
Enample 5: An apple with the mass of 200 g falls from a tree. What is the acceleration
of the apple towards the earth? What is the acceleration of the earth towards the apple?
(Given: mass of the earth = 6*10kg radius of the earth 6.4 10 m, G=6.67 * 10 " Nm
kg and neglecting height of the tree).​

Answer 1

Answer:

Acceleration of the apple towards the earth is: 9.7705 m/s2.

Acceleration produced on earth towards the apple

$0.325*10^{-24} \ \ m/s2.$

Explanation:

Given :

$m = 200 g$

We have to convert into the kg ,

so

$m=0.2 kg$

M=$6*10^{24}$ kg

$R=6.4*10^{6} m$

$G= 6.67*10^{-11} \ Nm^{2} kg-2$

As the gravitational force is existing among the earth and the apple

so

$F=\frac{GMm}{R^{2} }$

Putting the value of G,M,m and $R^{2}$, we get

$\frac{6.67*10^{-11} *6*10^{24} *0.2 }{(6.4*10^{6} )^{2} } \\\\F= 1.9541\ N$

Consider a1 and a2 be a acceleration due to the gravitational force of earth attraction created on the apples

F= a1 *m

$a1\ =\ \frac{F}{m}$

a1=$\frac{1.9541}{0.2}$

$a1=9.7705 \ m/s2$

Acceleration of the apple towards the earth is: 9.7705 m/s2.

again

$F= a2 *M$

a2=$\frac{F}{M}$

$a2=\frac{ 1.9541}{6**10^{24} } \\a2=0.325* 10^{-24}\ m/s2$

So, Acceleration produced on earth towards the apple

$0.325*10^{-24} \ \ m/s2.$