Answer:
(c)1/6
(d)5/12
Step-by-step explanation:
When two fair six-sided dice are rolled once
(a)The pair (x,y) denotes a single outcome of the experiment where x is the outcome of the first die and y is the outcome of the second die.
For example, (2,1) means the first die shows a 2 while the second die shows an outcome of 1.
(b)Sample Space
The sample space of all possible outcome is:
[tex](1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6)\\(2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6)\\(3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6)\\(4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6)\\(5, 1), (5, 2), (5, 3), (5, 4), (5, 5),(5,6)\\(6, 1), (6, 2), (6, 3), (6, 4), (6,5), (6,6)[/tex]
Total Number of Outcomes =36
(c)The probability for the first die to be two
The outcomes where the fist die is 2 are:
[tex](2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6)[/tex]
Therefore:
The probability for the first die is two
[tex]=\dfrac{6}{36}\\\\=\dfrac{1}{6}[/tex]
(d)The probability that the value rolled on die 1 minus the value rolled on die 2 is positive
These are the outcomes of the pair (x,y) where x>y.
They are:
[tex](2, 1)\\(3, 1), (3, 2)\\(4, 1), (4, 2), (4, 3)\\(5, 1), (5, 2), (5, 3), (5, 4)\\(6, 1), (6, 2), (6, 3), (6, 4), (6,5)[/tex]
[tex]P(x-y>0)=\dfrac{15}{36}\\\\=\dfrac{5}{12}[/tex]