Respuesta :
Answer:
(b) electrons will not be ejected
Explanation:
Determine the number of photons ejected by 10 W red laser pointer.
The wavelength (λ) of red light is 700 nm = 700 x 10⁻⁹ m
Energy of a photon is given as;
[tex]E = \frac{hc}{\lambda}[/tex]
where;
h is Planck's constant, = 6.626 x 10⁻³⁴ J/s
c is speed of light, = 3 x 10⁸ m/s
[tex]E = \frac{6.626*10^{-34} *3*10^8}{700 X 10^{-9}} \\\\E = 2.8397 *10^{-19} \ J/photon[/tex]
The number of photons emitted by 10 W red laser pointer
10 W = 10 J/s
[tex]Number \ of \ photons = 10(\frac{ J}{s}) * \frac{1}{2.8397*10^{-19}} (\frac{photon}{J} ) = 3.522 *10^{19} \ photons/s[/tex]
Determine the number of photons ejected by 5 W red green pointer
The wavelength (λ) of green light is 500 nm = 500 x 10⁻⁹ m
[tex]E = \frac{hc}{\lambda} = \frac{6.626*10^{-34} *3*10^8}{500*10^{-9}} = 3.9756 *10^{-19} \ J/photon[/tex]
The number of photons emitted by 5 W green laser pointer
5 W = 5 J/s
[tex]Number \ of \ photons = \frac{5J}{s} *\frac{photon}{3.9756*10^{-19}J} = 1.258 *10^{19} \ Photons/s[/tex]
The number of photons emitted by 10 W red laser pointer is greater than the number of photons emitted by 5 W green laser pointer.
Thus, 5 W green laser pointer will not be able to eject electron from the same metal.
The correct option is "(b) electrons will not be ejected"