Step-by-step explanation:
A) The amount is taken during the first dose is - 500 mg
In 10 days, she will take the drugs for 240/12 = 20 times
After 12 hours, 4.5 % of drugs remain in the blood therefore
after the first dose = 500
second dose, 4.5% of 500 + 500 = 22.5 +500 = 522.5 mg
third dose, 4.5 % of 522. 5 + 500 = 523.51 mg
Forth dose, 4. 5% of 523.51 + 500 = 523.55 mg
B) Highest amount will be found on 20th dose.
= 500 x (1-0.045^20/ 1- 0.045)
= 523.55 mg
C) The highest amount in the body is near to 523.55 mg therefore after 10 days also, the amount of drug will remain near the value of 523.55 mg.