The question is incomplete, however, the correct question is attached
in the image format:
Answer:
B. 171 N
Explanation:
The equation of the forces along the
Horizontal direction:
[tex]T_{2} cos62^{0} = T_{1} cos20^{0}[/tex]...... 1
Verticalb direction:
[tex]T_{1} sin20^{0} = T_{2} sin62^{0}[/tex] = W . . . 2
Where W = 180 N is the weight of the box.
From equation (1),
[tex]= T_{1} =T_{2} \frac{cos62^{0}}{ cos20^{0}}[/tex]
Substituting into equation (2),
[tex](T_{2} \frac{cos62^{0}}{ cos20^{0}})[/tex][tex]sin20^{0} = T_{2} sin62^{0}[/tex]
= [tex]T = \frac{W}{cos62x^{0} tan20x^{0}+sin62x^{0} }[/tex]
=117 N
Thus, the correct answer is option B. 117 N