Respuesta :

The question is incomplete, however, the correct question is attached

in the image format:

Answer:

B. 171 N

Explanation:

The equation of the forces along the

Horizontal direction:

[tex]T_{2} cos62^{0} = T_{1} cos20^{0}[/tex]...... 1

Verticalb direction:

[tex]T_{1} sin20^{0} = T_{2} sin62^{0}[/tex] = W . . . 2

Where W = 180 N is the weight of the box.

From equation (1),

[tex]= T_{1} =T_{2} \frac{cos62^{0}}{ cos20^{0}}[/tex]

Substituting into equation (2),

[tex](T_{2} \frac{cos62^{0}}{ cos20^{0}})[/tex][tex]sin20^{0} = T_{2} sin62^{0}[/tex]

= [tex]T = \frac{W}{cos62x^{0} tan20x^{0}+sin62x^{0} }[/tex]

=117 N

Thus, the correct answer is option B. 117 N

Ver imagen Histrionicus