Question

Suppose the time it takes a barber to complete a haircuts is uniformly distributed between 8 and 22 minutes, inclusive. Let X = the time, in minutes, it takes a barber to complete a haircut. Then X ~ U (8, 22). Find the probability that a randomly selected barber needs at least 14 minutes to complete the haircut, P(x > 14) (round answer to 4 decimal places) Answer:

Answer 1

Answer:

$P(X>14)= 1-P(X<14) =1- F(14)$

And replacing we got:

$P(X>14)= 1- \frac{14-8}{22-8}= 0.5714$

The probability that a randomly selected barber needs at least 14 minutes to complete the haircut is 0.5714

Step-by-step explanation:

We define the random variable of interest as x " time it takes a barber to complete a haircuts" and we know that the distribution for X is given by:

$X \sim Unif (a= 8, b=22)$

And for this case we want to find the following probability:

$P(X>14)$

We can find this probability using the complement rule and the cumulative distribution function given by:

$P(X<x) = \frac{x-a}{b-a} ,a \leq x \leq b$

Using this formula we got:

$P(X>14)= 1-P(X<14) =1- F(14)$

And replacing we got:

$P(X>14)= 1- \frac{14-8}{22-8}= 0.5714$

The probability that a randomly selected barber needs at least 14 minutes to complete the haircut is 0.5714