Question

To the nearest tenth, which is the perimeter of ABC. Geometry

Answer 1

Answer:

23.6

Step-by-step explanation:

Finding AC:

Cos 61 = $\frac{adjacent}{hypotenuse}$

0.48 × 10 = Adjacent

AC = 4.8

Now, CB:

Cos 29 = $\frac{adjacent}{hypotenuse}$

0.87 × 10 = CB

CB = 8.8

The perimeter:

=> 10+4.8+8.8

=> 23.6

Answer 2

Answer:

23.6

Step-by-step explanation: