Question

(08.03 MC)
Solve for x using the Quadratic Formula: x2 - 6x + 9 = 0
-bt/6².
-4ac
X=
2a
A. x = 6
B. x = 3
C. x=1
D. x=0

Answer 1

Answer:

B. x = 3

Step-by-step explanation:

You really don't need to quadratic formula for this. It would take too much time. Instead, factor out the equation:

(x -3)(x - 3) = 0

Once you found that, you should see that your roots will equal to 3.

Answer 2

Answer:

x=3

solution,

Rewrite x^2-6x+9 in the form a^2-2ab+b^2 where a=X and b=3.

${x}^{2} - 2(x)(3) + {3}^{2} = 0$

Use square of difference,

${(a - b)}^{2} = {a}^{2} - 2ab + {b}^{2} \\ {(x - 3)}^{2} = 0$

Take the square root of both sides

$x - 3 = 0$

Add 2 to both sides,

$x - 3 + 3 = 0 + 3 \\ x = 3$

hope this helps..

Good luck on your assignment..