Question

If the endpoints of AB have the coordinates A (9,8) and B(-1,-2), what is the midpoint of AB?

Answer 1

Answer:

(4,3)

Solution,

A(9,8)------->(X1,x2)

B(-1,-2)------->(x2,y2)

Now,

$ab = ( \frac{x1 + x2}{2} ,\frac{y1 + y2}{2} ) \\ \: \: \: \: \: = ( \frac{9 + ( - 1)}{2} \: ,\frac{8 + ( - 2)}{2} ) \\ \: \: \: \: \: = ( \frac{9 - 1}{2} ,\: \frac{8 - 2}{2} ) \\ \: \: \: = ( \frac{8}{2} ,\: \frac{6}{2} ) \\ \: \: \: = (4 , 3)$

hope this helps...

Good luck on your assignment....

Answer 2

Answer:

4,3

Step-by-step explanation:

$\frac{x_{1} + x_{2} }{2} , \frac{y_{1} + y_{2} }{2}$

$\frac{9-1}{2} = \frac{8}{2} =4$

$\frac{8-2}{2} = \frac{6}{2} =3$