Answer:
67 cookies
Step-by-step explanation:
When packaging in groups of 4, the possible number of cookies is x = (4n+3). The possible values are:
7, 11, 15, 19, 23, 27, 31, 35, 39, 43, 47, 51, 55, 59, 63, 67, 71...
When packaging in groups of 5, the possible number of cookies is x = (5n+2). The possible values are:
7, 12, 17, 22, 27, 32, 37, 42, 47, 52, 57, 62, 67, 72, 77...
When packaging in groups of 7, the possible number of cookies is x = (7n+4). The possible values are:
11, 18, 25, 32, 39, 46, 53, 60, 67, 74, 81, 88, 95...
The least value that appears on all three possibilities is 67, therefore the least number of cookies that Mohan could have is 67.