Answer:
For the revenue per month to drop, the price per boat per month has to drop more than $2,000
Explanation:
Given:
Number of boats sold per month = 50
Cost of each boat = $25,000
Each month demand increases at a rate of 4 boats per month.
Required:
Find the fastest price could drop before monthly revenue starts to drop.
Revenue, R = Price × Quantity
R = P × Q
Differntiate both sides with respect to time, t:
[tex] \frac{dR}{dt} = \frac{dP}{dt} Q + \frac{dQ}{dt} P [/tex]
[tex] = \frac{dP}{dt} 50 + 4 * 25,000[/tex]
For the fastest price could drop before monthly revenue starts to drop, [tex] \frac{dR}{dt} < 0 [/tex]
Thus,
[tex] = \frac{dP}{dt} 50 + 4 * 25,000 < 0[/tex]
[tex] = \frac{dP}{dt} 50 + 100,000 < 0[/tex]
[tex] = \frac{dP}{dt} 50 < -100,000 [/tex]
[tex] \frac{dP}{dt} = \frac{-100,000}{50} [/tex]
[tex] \frac{dP}{dt} = -2,000[/tex]
Since the answer is negative, it indicates a drop in price.
Therefore, for the revenue per month to drop, the price per boat per month has to drop more than $2,000