Question

A painter leans a 10 ft ladder against a building.
The base of the ladder is 7 ft from the building.
To the nearest foot, how high on the building
does the ladoer reach?

Answer 1

Answer:

7.14 ft

I hope it helps :)

Step-by-step explanation:

$Hypotenuse = 10\\Opposite = 7\\Adjacent = x\\ \\Using Pythagoras theorem ;\\Hyp^{2} =opp^{2} +adj^{2} \\10^{2} = 7^{2} +x^{2} \\100 = 49+x^{2} \\x^{2} =100-49\\x^{2} =51\\\sqrt{x^{2} } =\sqrt{51} x = 7.14 ft$