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Answer:
Step-by-step explanation:
Parallel lines have same slope
19) y = x - 4
m = 1 ; (2, 3 )
Equation: y - y₁ = m(x- x₁)
y - 3 = 1(x - 2)
y - 3 = x -2
y = x - 2 + 3
y = x + 1
20) 2x + 3y = 3
We have to write in y = mx + b form
3y = - 2x - 3
[tex]y=\frac{-2}{3}x-\frac{3}{3}\\\\y=\frac{-2}{3}x-1\\\\m=\frac{-2}{3}[/tex]; (-6, -1)
[tex]y-[-1]=\frac{-2}{3}(x-[-6])\\\\y+1=\frac{-2}{3}(x+6)\\\\y+1=\frac{-2}{3}x+\frac{-2}{3}*6\\\\y+1=\frac{-2}{3}x-4\\\\y=\frac{-2}{3}x-4-1\\\\y=\frac{-2}{3}x-5[/tex]
for perpendicular lines, m2 = -1/m1
21) y = 2x+ 5
m1 = 2
[tex]m_{2}=\frac{-1}{2}[/tex]; (-2,8)
[tex]y-8=\frac{-1}{2}(x-[-2])\\\\y-8=\frac{-1}{2}(x+2)\\\\y-8=\frac{-1}{2}x+2*\frac{-1}{2}\\\\y-8=\frac{-1}{2}x-1\\\\y=\frac{-1}{2}x-1+8\\\\y=\frac{-1}{2}x+7[/tex]
22) x+ 4y = 8
4y = -x + 8
[tex]y=\frac{-1}{4}x+\frac{8}{4}\\\\y=\frac{-1}{4}x+2\\\\m_1=\frac{-1}{4}\\\\m_{2}=4\\\\[/tex]
m2 = 4; (-2,-11)
y - [-11] = 4(x -[-2])
y + 11 = 4 (x + 2)
y + 11 = 4x + 8
y = 4x + 8 - 11
y = 4x - 3