Respuesta :

Given:

Four different positive intergers as a product of 110

To find:

The sumnof the four numbers whose product is 110

Solution:

1) To find the number we have to find the prime factorization of the given number 110

2) Prime factorization of 110 is

110 = 1×2 × 5 = 11

3) So the four numbers whose product is 110 are 1,2,5 and 11

4) The sum of number's are

1+2+5+11=19

SO THE FINAL ANSWER IS 19

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