Answer: [tex]\bold{\ln \bigg(\dfrac{x^2}{9}\bigg)}[/tex]
Step-by-step explanation:
[tex]2\ln e^{\ln(5x)}-2\ln 15\\\\\\= \ln (e^{\ln(5x)})^2-2\ln 15\\\\\\= \ln(5x)^2-ln(15)^2\\\\\\= \ln\bigg(\dfrac{(5x)^2}{(15)^2}\bigg)\\\\\\= \ln\bigg(\dfrac{25x^2}{225}\bigg)\\\\\\=\large\boxed{\ln \bigg(\dfrac{x^2}{9}\bigg)}[/tex]
