Question

What is the approximate volume of a cone with a height of 9 ft and radius of 3 ft? Use 3.14 to approximate pi, and express your final answer to the nearest hundredth. Enter your answer as a decimal in the box. [ ] ft³

Answer 1

Answer:

84.78 ft^3

Solution,

Radius=3 ft

Height=9 ft

Volume of cone=?

Now,

$volume \: of \: cone \\ = \frac{1}{2}\pi \: {r}^{2} h \\ = \frac{1}{2} \times 3.14 \times {3}^{2} \times 9 \\ = \frac{1}{2} \times 3.14 \times 9 \times 9 \\ = 84.78 \: {ft}^{3}$

hope this helps...

Good luck on your assignment

Answer 2

Answer:

V = 84.82 ft³

Step-by-step explanation:

Volume of Cone = $\pi r^2\frac{h}{3}$

Where r = 3, h = 9

=> V = $(3.14)(3)^2(\frac{9}{3} )$

=> V = (3.14)(9)(3)

=> V = 84.82 ft³